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The Cleveland Cavaliers have made their first signing of the summer.
The team it announced through a press release Wednesday afternoon that it has signed Collin Sexton, its 2018 first-round draft choice.
The former Alabama star’s rookie contract is a four-year, $20.2 million deal. The most he could earn as a rookie, per NBA rules, is $4.1 million, based on where he was taken in the draft, eighth overall. The first two years of the contract are guaranteed, with Years 3 and 4 being team options.
With Sexton having signed the deal, he cannot be traded to 30 days, also per NBA rules. That doesn’t seem likely.
“We’re going to invest a lot of time into him and he’s a part of this culture now of winning, of hard work, attitude, the stuff we talk about,” Cavaliers general manager Koby Altman said of the point guard during Sexton’s introductory press conference last month.
Sexton will make his on-court debut with Cleveland as part of its team in the Las Vegas Summer League, which tips off Friday.
The singing of Sexton puts the Cavaliers with 12 players under contract, with three open roster spots. One will most likely be filled by Rodney Hood, a restricted free agent. Cleveland has the right to match any offer he receives and reportedly intends to do so.