Latest posts by Colton Jones (see all)
- Bucks add Young, Johnson, waive Barnett, McCoy - September 18, 2018
- Big man Moreland signs Exhibit 10 pact with Raptors - September 18, 2018
- 76ers hire Brand as general manager - September 18, 2018
The Cleveland Cavaliers have high hopes for Collin Sexton.
Selected with the eighth overall pick in the draft June 21, his peers are also expecting the point guard out of Alabama to shine.
Sexton, along with No. 1 overall pick DeAndre Ayton of the Phoenix Suns, tied for voting to be the 2019 NBA Rookie of the Year in a vote by their peers.
NBA.com collected the votes at the league’s rookie event and both Sexton and Ayton received 18 percent of the votes cast. Players were not permitted to vote for themselves or their teammates. Fifteen players received at least one vote.
Who will be the 2018-19 Rookie of the Year?
1. Collin Sexton, Cleveland — 18 percent
DeAndre Ayton, Phoenix — 18 percent
3. Luka Doncic, Dallas — 9 percent
Kevin Knox, New York — 9 percent
5. Mohamed Bamba, Orlando — 6 percent
Devonte’ Graham, Charlotte — 6 percent
Michael Porter Jr., Denver — 6 percent
Trae Young, Atlanta — 6 percent
Others receiving votes — Marvin Bagley III, Sacramento; Troy Brown Jr., Washington; Wendell Carter Jr., Chicago; Hamidou Diallo, Oklahoma City; Harry Giles, Sacramento; Jaren Jackson Jr., Memphis; Lonnie Walker IV, San Antonio. — NBA.com
Keita Bates-Diop out of Ohio State, selected y the Minnesota Timberwolves in the second round with the 48th overall selection, was voted steal of the draft.
Trae Young of the Atlanta Hawks was selected as the best rookie shooter, while Wendell Carter Jr. of the Chicago Bulls was predicted to have the best NBA career.
Sexton, 19, stood out for the Cavaliers’ squad in the Las Vegas Summer League last month, averaging 19.6 points, 3.6 rebounds and 3.4 assists. He was named first-team All-Summer League.
Twenty-nine percent of the rookies named former Cavalier and now Laker LeBron James as their favorite NBA player.